(3x^2y^2+2)dy+(2xy^3-3)dx=0

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Solution for (3x^2y^2+2)dy+(2xy^3-3)dx=0 equation: 


Simplifying
(3x2y2 + 2) * dy + (2xy3 + -3) * dx = 0

Reorder the terms:
(2 + 3x2y2) * dy + (2xy3 + -3) * dx = 0

Reorder the terms for easier multiplication:
dy(2 + 3x2y2) + (2xy3 + -3) * dx = 0
(2 * dy + 3x2y2 * dy) + (2xy3 + -3) * dx = 0

Reorder the terms:
(3dx2y3 + 2dy) + (2xy3 + -3) * dx = 0
(3dx2y3 + 2dy) + (2xy3 + -3) * dx = 0

Reorder the terms:
3dx2y3 + 2dy + (-3 + 2xy3) * dx = 0

Reorder the terms for easier multiplication:
3dx2y3 + 2dy + dx(-3 + 2xy3) = 0
3dx2y3 + 2dy + (-3 * dx + 2xy3 * dx) = 0
3dx2y3 + 2dy + (-3dx + 2dx2y3) = 0

Reorder the terms:
-3dx + 3dx2y3 + 2dx2y3 + 2dy = 0

Combine like terms: 3dx2y3 + 2dx2y3 = 5dx2y3
-3dx + 5dx2y3 + 2dy = 0

Solving
-3dx + 5dx2y3 + 2dy = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), 'd'.
d(-3x + 5x2y3 + 2y) = 0


Subproblem 1
Set the factor 'd' equal to zero and attempt to solve:

Simplifying
d = 0

Solving
d = 0

Move all terms containing d to the left, all other terms to the right.

Simplifying
d = 0

Subproblem 2
Set the factor '(-3x + 5x2y3 + 2y)' equal to zero and attempt to solve:

Simplifying
-3x + 5x2y3 + 2y = 0

Solving
-3x + 5x2y3 + 2y = 0

Move all terms containing d to the left, all other terms to the right.

Add '3x' to each side of the equation.
-3x + 5x2y3 + 3x + 2y = 0 + 3x

Reorder the terms:
-3x + 3x + 5x2y3 + 2y = 0 + 3x

Combine like terms: -3x + 3x = 0
0 + 5x2y3 + 2y = 0 + 3x
5x2y3 + 2y = 0 + 3x
Remove the zero:
5x2y3 + 2y = 3x

Add '-5x2y3' to each side of the equation.
5x2y3 + -5x2y3 + 2y = 3x + -5x2y3

Combine like terms: 5x2y3 + -5x2y3 = 0
0 + 2y = 3x + -5x2y3
2y = 3x + -5x2y3

Add '-2y' to each side of the equation.
2y + -2y = 3x + -5x2y3 + -2y

Combine like terms: 2y + -2y = 0
0 = 3x + -5x2y3 + -2y

Simplifying
0 = 3x + -5x2y3 + -2y

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
d = {0}

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